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[xsl] <xsl:when test="position()%2=0">

Subject: [xsl] <xsl:when test="position()%2=0">
From: "Luke Ambrogio" <gryzlaw@xxxxxxxxxxx>
Date: Mon, 21 Apr 2003 17:09:18 +0200 (W. Europe Daylight Time)
first of all i wish to thank all of you guys (and gals) for providing me with great help. now i have another query
 
i would like to find the position of a node whether it is odd or even, and tried to use position() mod 2, but i don't know how to do it
 
can anyone tell me how to find the remainder of a division or else any ideas on how to find whether a node is odd or even
 
10x, regards
luke
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