[xsl] using fn:max with Saxon 7.4 ?

Subject: [xsl] using fn:max with Saxon 7.4 ?
From: "malcolm macaulay" <malcolm_xslt_list@xxxxxxxxxxx>
Date: Wed, 23 Apr 2003 02:29:41 +1200
Can some please help me with using the new XPath 2.0 functions in Saxon 7.4?

When I try the transformation detailed below I get the following error:

"Unknown function fn:min". The other day Saxon was telling me it did not recognise the fn namespace, although I can't reproduce that now.

Apologies if this problem has been explained many times over - I've been off-list for quite a while and didn't have any luck with the archives.

cheers

Malcolm

XML:

<?xml version="1.0" encoding="UTF-8"?>
<numbers>
	<number>3</number>
	<number>5</number>
	<number>10</number>
	<number>1</number>
</numbers>

XSLT:

<xsl:transform xmlns:xsl="http://www.w3.org/1999/XSL/Transform"; xmlns:fn="http://www.w3.org/2002/11/xquery-functions"; xmlns:saxon="http://saxon.sf.net/"; version="2.0">
<xsl:template match="/">
<max>
<xsl:value-of select="fn:max(numbers/number)"/>
<!-- this works of course..
<xsl:value-of select="saxon:max(numbers/number)"/>
-->
</max>
</xsl:template>
</xsl:transform>





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