Re: [xsl] Grouping problem?

["Simon Kelly" <kelly@xxxxxxxxxx>]

Hi Benjamin,

I can't actually test this solution as I don't use saxon, but if you can
then this may work out ok.


Up the top somewhere define an assignable variable

<xsl:variable name="count" select="0" saxon:assignable="yes" />

then

<xsl:template match="/root">
  <xsl:apply-templates />
</xsl:template>

<xsl:template match="ele">
  <xsl:choose>
    <xsl:when test="position() = 1">
      <xsl:variable name="count" select="sum(./@sum)" />
      <xsl:copy>
        <xsl:apply-templates select="node()|@*" />
      </xsl:copy>
    </xsl:when>
    <xsl:when test="$count < 10">
      <xsl:choose>
        <xsl:when test="($count + sum(./@sum)) >= 10">
          <br/>
          <xsl:variable name="count" select="sum(./@sum)" />
          <xsl:copy>
            <xsl:apply-templates select="node()|@*" />
          </xsl:copy>
        </xsl:when>
        <xsl:otherwise>
          <xsl:variable name="count" select="$count + sum(./@sum)" />
          <xsl:copy>
            <xsl:apply-templates select="node()|@*" />
          </xsl:copy>
        </xsl:otherwise>
      </xsl:choose>
    <xsl:otherwise>
      <br />
      <xsl:variable name="count" select="sum(./@sum)" />
      <xsl:copy>
        <xsl:apply-templates select="node()|@*" />
      </xsl:copy>
    </xsl:otherwise>
  </xsl:choose>
</xsl:template>


It's a bit long winded but it should work.  The last <xsl:otherwise /> in
the main <xsl:choose /> takes care of any first nodes that are greater than
10.  This should also work for any ele grouping like

<root>
  <set val="1">
    <ele sum="1" />
    ...
    <ele sum="n" />
  </set>
  <set val="N">
    <ele sum="2" />
    ...
    <ele sum="N" />
  </set>
</root>

with a minor mod to the calling template.

Cheers

Simon


----- Original Message -----
From: "Benjamin Farrow" <lovinjess@xxxxxxxxxxx>
To: <xsl-list@xxxxxxxxxxxxxxxxxxxxxx>
Sent: Tuesday, April 22, 2003 9:06 PM
Subject: [xsl] Grouping problem?


> All,
>   I don't know how to explain my problem in words very concisely, so I'll
> try with a simplified example.
>
> SourceXML:
> <root>
>   <ele sum="3"/>
>   <ele sum="4"/>
>   <ele sum="2"/>
>   <ele sum="10"/>
>   <ele sum="7"/>
>   <ele sum="5"/>
>   <ele sum="1"/>
>   <ele sum="2"/>
> </root>
>
> Desired Output:
> <root>
>   <ele sum="3"/>
>   <ele sum="4"/>
>   <ele sum="2"/>
>   <br/>          <!-- next element makes total greater than 10 -->
>   <ele sum="10"/>
>   <br/>          <!-- next element makes total greater than 20 -->
>   <ele sum="7"/>
>   <br/>          <!-- next element makes total greater than 30 -->
>   <ele sum="5"/>
>   <ele sum="1"/>
>   <ele sum="2"/>
> </root>
>
> I'm trying to break apart the ele element when the sum total of preceding
> siblings and self is greater than the increment of 10 by putting an
element
> to denote the break.
>
> I've tried some crazy tests with mod and div and I've looked over the
> Muenchian grouping, but I still can't come up with a way to arbitrarily
set
> the break points.  I know there is a solution and I get close, but I just
> can't get around it.
>
> Here is my template (also have the standard identity template) with which
> I'm trying to get this working.  I just can't figure out the if test for
> this though.
>
> XSL:
>   <xsl:template match="ele">
>     <xsl:variable name="sum"
> select="sum(preceding-sibling::ele/@sum|@sum)"/>
>     <xsl:if test="$sum &gt; (floor($sum div 10) * 10)">
>       <br/>
>     </xsl:if>
>     <xsl:copy>
>       <xsl:apply-templates select="node()|@*"/>
>     </xsl:copy>
>   </xsl:template>
>
> Thanks in advance,
>   Benjamin
>
>
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