[xsl] Show YEAR once if the YEAR same as preious element by xsl

["Cheung Tin Po" <timothy298@xxxxxxxxxxx>]

hi expert,

i get the following XML file

<record>
<row year="2001" month="1">
<row year="2001" month="2">
<row year="2001" month="3">
<row year="2001" month="4">
<row year="2002" month="1">
<row year="2002" month="2">
<row year="2002" month="3">
<row year="2003" month="1">
<row year="2003" month="2">
</record>

i want to transform it to html with the following result

2001/1
    2
    3
    4
2002/1
    2
    3
2003/1
    2


as XSLT cannot store the variable  so i cannot think any method to should 
the result.

:<
> From Timothy


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