RE: [xsl] Generating serial no.s for XML tags

[Mukul <mukulw3@xxxxxxxxx>]

Thank you for reply. This is exactly I needed. Its
quite simple. Thanks Marcus for your reply also .. 

Regards,
Mukul

--- Jarno.Elovirta@xxxxxxxxx wrote:
> Hi,
> 
> > I want to write a XSLT which displays serial no.s
> as
> > the <tag> TAGs are found
> > 
> > I have written a XSL as below -
> > <?xml version="1.0" encoding="UTF-8"?>
> > <xsl:stylesheet version="1.0"
> > xmlns:xsl="http://www.w3.org/1999/XSL/Transform"; >
> > <xsl:template match="rootelem/tag">
> >      <xsl:value-of select="count(preceding::tag) +
> 1"
> > />
> >      
> >      <xsl:if test="total">
> >           <xsl:value-of
> select="count(preceding::tag)
> > + 1" />
> >      </xsl:if>
> > 
> > </xsl:template>
> > </xsl:stylesheet>
> > 
> > I want that when <total> tag comes , an extra
> serial
> > no. gets generated which is one more than the
> previous
> > one. After the serial no. of <total> tag is o/p,
> the
> > next serial no. resumes as 1 more than this.
> > 
> > The above stylesheet is generating output as
> 122345566
> > . I want the o/p to come as 123456789(this
> includes
> > serial no.s for <total> tag).
> 
> <xsl:template match="tag">
>   <xsl:variable name="x"
> select="count(preceding::tag) +
> count(preceding::tag[total]) + 1" />
>   <xsl:value-of select="$x"/>
>   <xsl:if test="total">
>     <xsl:value-of select="$x + 1" />
>   </xsl:if>
> </xsl:template>
> 
> But you might want to consider writing e.g. a
> recursive template to generate the serial number to
> eliminate the use of preceding axis.
> 
> Cheers,
> 
> Jarno - Assemblage 23: Document (Endanger Mix)
> 
>  XSL-List info and archive: 
> http://www.mulberrytech.com/xsl/xsl-list
> 


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