Fw: [xsl] Obtain XSL content

[Márcio Fernando Keller <marcio@xxxxxxxxxxxxx>]

 I would like, in some situations, to show a more friendly way to the user
 define the xsl content.
 Example:
 
         <xsl:choose>
             <xsl:when test="/Orders/SalesOrder/Customer/Gender='F'">
                 <xsl:text>Female</xsl:text>
             </xsl:when>
            <xsl:when test="/Orders/SalesOrder/Customer/Gender='M'">
               <xsl:text>Male</xsl:text>
            </xsl:when>
         </xsl:choose>
 
 For the user, i would like to show:
 -------------------------
  Source        | Target
 -------------------------
 F                 | Female
 M                | Male
                    |
 -------------------------
 
 .... and permit to change this.
 
Question:
I think that i can use parser classes(ex xalan), xpath or process it like
another xml file, but what the best method for this?
Examples?

 Thanks
 
 
| ----- Original Message -----
| From: "Michael Kay" <mhk@xxxxxxxxx>
| To: <xsl-list@xxxxxxxxxxxxxxxxxxxxxx>
| Sent: Monday, May 12, 2003 10:03 PM
| Subject: RE: [xsl] Obtain XSL content
| 
| 
| | >
| | > What is the best way to obtain the content of a xsl file. ...
| | >
| | > I need to know that exist a template  for
| | > "/Orders/SalesOrder/Customer/Gender" and tests with choose,
| |
| | You can read the stylesheet using document(''), as if it were another
| | XML document.
| |
| | But it would be nice to know why you think you need to do this: what is
| | the problem you are trying to solve?
| |
| | Michael Kay
| |
| |
| |  XSL-List info and archive:  http://www.mulberrytech.com/xsl/xsl-list
| |
| 
| 
|  XSL-List info and archive:  http://www.mulberrytech.com/xsl/xsl-list
| 

 XSL-List info and archive:  http://www.mulberrytech.com/xsl/xsl-list