Re: [xsl] Strange Problem with document($variablename)

[Jeni Tennison <jeni@xxxxxxxxxxxxxxxx>]

Hi Torsten,

> Using <p><xsl:value-of select="$filename"/></p> the correct filename
> is being printed.
>
> (For example ../content/news/foo" if @name == foo.)
>
> Using document($filename) I get a java.io.FileNotFound exception for
> "../content/news/" (where is the foo gone; it the identical
> variable!!!).

That's very peculiar. If you want an equivalent variable, try using
the concat() function:

<xsl:variable name="filename"
              select="concat('../content/news/', @name)" />

I doubt that it will give you a different result.

By the way, the reason that the file isn't found might be because the
URL is being resolved relative to the directory that the stylesheet
lives in rather than the directory that the XML document lives in. Try
using:

  document($filename, .)

to get the $filename URL to be resolved relative to the current
<directory> element.

Cheers,

Jeni

---
Jeni Tennison
http://www.jenitennison.com/


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