[xsl] RE: Using a reference in a sort

["Jesse M. Heines" <heines@xxxxxxxxxx>]

> Try <xsl:sort
>
select="document($filePeople)/people/person[@id=current()/person/@id]/@l
ast"
>   order="descending"/> instead

Thanks for your reply, but I'm sorry to report that that doesn't work
either.  The context of current() is still the node in the other XML
file.  The documentation I have says that current() is the same as ".",
which I tried and does not help, either.

More suggestions, please!

Jesse




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