RE: RE: RE: [xsl] xsl:output method=xml

["Frank J. Buono" <Frank.Buono@xxxxxxxxxxxxxxxxxxxxxxx>]

It IS nasty. :) HOwever, I'm a novice at this and I had to produce "<", ">", and "</".
This code gets me: "<name>text</name>". copy-of worked great; however, it gave
me a few extra lines that I couldn't seem to get rid of...

            <xsl:for-each select="child::*">
              <xsl:text disable-output-escaping="yes">&lt;</xsl:text>
              <xsl:value-of select="name()"/>
              <xsl:text disable-output-escaping="yes">&gt;</xsl:text>
              <xsl:value-of select="text()"/>
              <xsl:text disable-output-escaping="yes">&lt;/</xsl:text>
              <xsl:value-of select="name()"/>
              <xsl:text disable-output-escaping="yes">&gt;</xsl:text>
            </xsl:for-each>

-----Original Message-----
From: cknell@xxxxxxxxxx [mailto:cknell@xxxxxxxxxx]
Sent: Wednesday, July 30, 2003 4:54 PM
To: xsl-list@xxxxxxxxxxxxxxxxxxxxxx
Subject: RE: RE: RE: [xsl] xsl:output method=xml


That is uuuuuug-ly! There is almost never a reason to use disable-output-escaping. Trash everything inside the <xsl:for-each select="child::*"> element and replace it with this:

<xsl:element name="name()"><xsl:value-of select="text()"/></xsl:element>
-- 
Charles Knell
cknell@xxxxxxxxxx - email



-----Original Message-----
From:     "Frank J. Buono" <Frank.Buono@xxxxxxxxxxxxxxxxxxxxxxx>
Sent:     Wed, 30 Jul 2003 16:06:09 -0400
To:       <xsl-list@xxxxxxxxxxxxxxxxxxxxxx>
Subject:  RE: RE: [xsl] xsl:output method=xml


Thanks, Charles. This is what I ended up going with - kinda
brute force, but I'm a stylesheet novice:

<?xml version="1.0" encoding="UTF-8"?>
<xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform";>
   <xsl:output method="xml" version="1.0" encoding="UTF-8" indent="yes"/>
   <xsl:template match="ROWSET">
     <ROWSET>
       <xsl:for-each select="ROW">
       <xsl:sort select="value" data-type="number"/>
	 <ROW rownum="{position()}">
            <xsl:for-each select="child::*">
              <xsl:text disable-output-escaping="yes"><</xsl:text>
              <xsl:value-of select="name()"/>
              <xsl:text disable-output-escaping="yes">></xsl:text>
              <xsl:value-of select="text()"/>
              <xsl:text disable-output-escaping="yes"></</xsl:text>
              <xsl:value-of select="name()"/>
              <xsl:text disable-output-escaping="yes">></xsl:text>
            </xsl:for-each>
 	  </ROW>
	</xsl:for-each>
      </ROWSET>
    </xsl:template>
</xsl:stylesheet>

-----Original Message-----
From: cknell@xxxxxxxxxx [mailto:cknell@xxxxxxxxxx]
Sent: Wednesday, July 30, 2003 2:41 PM
To: xsl-list@xxxxxxxxxxxxxxxxxxxxxx
Subject: RE: RE: [xsl] xsl:output method=xml


Use the <xsl:copy-of> element. In the template below, change this line:
<ROW rownum="{@rownum}"><value><xsl:value-of select="." /></value></ROW>

to:
<xsl:copy-of select="." />
-- 
Charles Knell
cknell@xxxxxxxxxx - email



-----Original Message-----
From:     "Frank J. Buono" <Frank.Buono@xxxxxxxxxxxxxxxxxxxxxxx>
Sent:     Wed, 30 Jul 2003 13:42:46 -0400
To:       <xsl-list@xxxxxxxxxxxxxxxxxxxxxx>
Subject:  RE: [xsl] xsl:output method=xml


Thanks, Charles and Mukul. That code works great!
I was under the mistaken impression that "output method=xml"
would give me more XML tags of output.

I ultimately need to have my output XML look exactly
the same as my input XML but with the rows sorted column. Each
row could have several columns.

Is there a generic stylesheet example available that simply
passes everything through?

Thanks.

frank

<?xml version="1.0" encoding="UTF-8" ?>
<xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform";>
  <xsl:output method="xml" indent="yes" encoding="UTF-8" />
  <xsl:template match="/">
    <xsl:apply-templates />
  </xsl:template>

  <xsl:template match="ROWSET">
    <ROWSET>
    <xsl:for-each select="ROW">
      <xsl:sort select="value" data-type="number" order="ascending" />
      <ROW rownum="{@rownum}"><value><xsl:value-of select="." /></value></ROW>
    </xsl:for-each>
    </ROWSET>
  </xsl:template>
</xsl:stylesheet>
-- 
Charles Knell
cknell@xxxxxxxxxx - email



-----Original Message-----
From:     "Frank J. Buono" <Frank.Buono@xxxxxxxxxxxxxxxxxxxxxxx>
Sent:     Wed, 30 Jul 2003 10:02:07 -0400
To:       <XSL-List@xxxxxxxxxxxxxxxxxxxxxx>
Subject:  [xsl] xsl:output method="xml"


I've seen a lot of examples of outputing in HTML; however,
I'd like to sort on "value" and output in XML - see input and
desired output XML below.

Can anybody help with what my stylesheet should look like?

Thanks.

Frank
p.s., I'll be doing this within java code.

****Input:
<ROWSET>
   <ROW rownum="1">
      <value>3</value>
   </ROW>
   <ROW rownum="2">
      <value>1</value>
   </ROW>
   <ROW rownum="3">
      <value>2</value>
   </ROW>
</ROWSET>

*****Output:
<ROWSET>
   <ROW rownum="1">
      <value>1</value>
   </ROW>
   <ROW rownum="2">
      <value>2</value>
   </ROW>
   <ROW rownum="3">
      <value>3</value>
   </ROW>
</ROWSET>


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 XSL-List info and archive:  http://www.mulberrytech.com/xsl/xsl-list


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