[xsl] Using URL parameters in XSL

[Julian Wood <woodj@xxxxxxxxxxx>]

Hi,

I'm trying to gain access to the URL parameters used to load an xml 
file. For instance, can robin.xsl, used to process batman.xml, get the 
imageNum parameter in its URL?

http://bla.bla/batman.xml?imageNum=3

My xsl just needs this one param set (ie. equivalent to <xsl:param 
name="imageNum">3</xsl:param>)
so that it can conditionally process. This has to be local (ie no cgi 
allowed to write the stylesheet, as was discussed before on this list). 
I've looked high and low for this, but I can't find out how to retrieve 
the URL for manipulation. I've also looked into how to potentially 
manipulate the stylesheet with javascript, but this happens after the 
page has been transformed, and thus is too late.

Thanks for any help,

J

--
Julian Wood
Learning Commons, University of Calgary


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