Re: [xsl] limit count() to nodes with a position() < the postion of the current node

["M. David Peterson" <conners_dad@xxxxxxx>]

yes, this all makes sense now... Thank you for your help.  I will get this 
together, test it, and respond with the results for future reference.

Best Regards,

M.


----- Original Message ----- 
From: "Zink, Juergen" <Juergen.Zink@xxxxxxxxxxxxxxxxxxxx>
To: <xsl-list@xxxxxxxxxxxxxxxxxxxxxx>
Sent: Tuesday, September 09, 2003 1:36 AM
Subject: AW: [xsl] limit count() to nodes with a position() &lt; the postion 
of the current node


> Hi,
>
> the it is a grouping problem. Have a look at www.jenitennison.com
> Define a key with
>
> <xsl:key name="linkCount" match="visit" use="lid"/>
>
> >History >> Home(2) :: Section 2
>
> All Home are now grouped.
> Iterate above all the nodes foreach and check if
> it is the first element in a group. Then you can
> print (output) the element.
>
> <xsl:for-each select="//visit">
>
> <xsl:if test="generate_id(key('linkCount',lid))=generate-id(.)">
>
> Or you can count the number of items in the group.
> with count(key('linkCount', lid)) to get the (2) after Home
>
> >History >> Home(2) :: Section 2
>
> The code is not tested. Hope it works.
>
> Kind regards,
>
> Juergen
>
> -----Ursprüngliche Nachricht-----
> Von: M. David Peterson [mailto:conners_dad@xxxxxxx]
> Gesendet am: Dienstag, 9. September 2003 08:44
> An: xsl-list@xxxxxxxxxxxxxxxxxxxxxx
> Betreff: Re: [xsl] limit count() to nodes with a position() &lt; the
> postion of the current node
>
> Ah, yes, I see the mistake regarding the position() of the 'lid' node.
>
> What I am trying to do is this...  I have a history file that allows the
> user to view the last 5, 10, or 25 links they have visited on the site. 
> The
>
> count simply tells the user how many times they have visited that link. 
> To clean things up for them I want to check during each pass through the
> for-each loop if the link in there history file has already been rendered 
> to
>
> the output.  If it has then I want it to skip over that entry and move on 
> to
>
> the next.  So, for example, if the history file looked like this...
>
> <history>
>     <visit>
>         <loc>foo</loc>
>         <subloc>bar</subloc>
>         <lid>AAA001</lid>
>     </visit>
>     <visit>
>         <loc>foofoo</loc>
>         <subloc>barbar</subloc>
>         <lid>AAA002</lid>
>     </visit>
>     <visit>
>         <loc>foo</loc>
>         <subloc>bar</subloc>
>         <lid>AAA001</lid>
>     </visit>
> </history>
>
> Instead of the history output listing all the entries like this (I
> previously match the 'lid' to a master file to get the common name for the 
> link and then display the common name. e.g AAA001 = Home and AAA002 = 
> Section 2)...
>
> History >> Home :: Section 2 :: Home
>
> It would list it like this...
>
> History >> Home(2) :: Section 2
>
> Any ideas?
>
> Best regards,
>
> M.
>
>
>
>
> ----- Original Message ----- 
> From: "Zink, Juergen" <Juergen.Zink@xxxxxxxxxxxxxxxxxxxx>
> To: <xsl-list@xxxxxxxxxxxxxxxxxxxxxx>
> Sent: Tuesday, September 09, 2003 12:07 AM
> Subject: AW: [xsl] limit count() to nodes with a position() &lt; the 
> postion
>
> of the current node
>
>
> > Hi,
> >
> > the position of <lid> is the number of preceding siblings.
> > In your example should be 4, <loc>, <sub>, <date> sibling before.
> >
> > Maybe you can use a foreach with select="//lid".
> > All the lid elements in a node set in document order.
> > Then you can use position() within the loop.
> >
> > But I don't understand your questions fully.
> > What do you want to achieve?
> >
> > Kind regards,
> >
> > Juergen
> >
> > -----Ursprüngliche Nachricht-----
> > Von: M. David Peterson [mailto:conners_dad@xxxxxxx]
> > Gesendet am: Dienstag, 9. September 2003 07:23
> > An: xsl-list
> > Betreff: [xsl] limit count() to nodes with a position() &lt; the postion
> > of the current node
> >
> > Hi all,
> >
> > Ive got an interesting one for you...
> >
> > Ive got the following key...
> >
> > <xsl:key name="linkCount" match="lid" use="."/>
> >
> > that uses the following xml...
> >
> > <history>
> >     <visit>
> >       <loc>life</loc>
> >       <subloc>main</subloc>
> >       <date>9/8/2003 10:49:58 PM</date>
> >       <lid>AAD001</lid>
> >     </visit>
> > </history>
> >
> > to give me the total count of all nodes that have the value of the 
> > current
>
> > context...
> >
> > <xsl:value-of select="count(key('linkCount', lid))"/>
> >
> > This works perfectly as it returns the total count of all nodes that 
> > have > the same value as the current context node...
> >
> > But I want to take this one step further and return the count of all 
> > nodes
>
> > that have a position() that is less than the position of the current 
> > node.
>
> > Taking the position() of the context node out of the equation I thought 
> > it
>
> > would as simple as this (I used 5 as a test parameter)...
> >
> > <xsl:key name="linkCount" match="lid[position() &lt; 5]" use="."/>
> >
> > I expected it to return the count of the nodes that matched the current
> > context node as long as there postion was less than 5.  But it didn't. 
> > It
>
> > returned the total count for the entire xml tree.
> >
> > So, my questions are...  1)What do I need to change to get the above
> > example
> >
> > to work and 2)How could I then take it one step further and use the
> > position() of the current context node as the parameter to test against 
> > > the position() of the test nodes?
> >
> > Your help is much appreciated!
> >
> > Best Regards,
> >
> > M.David
> >
> >  XSL-List info and archive:  http://www.mulberrytech.com/xsl/xsl-list
> >
> >
> >
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