Subject: RE: [xsl] limit count() to nodes with a position() < the postion of the current node From: "Michael Kay" <mhk@xxxxxxxxx> Date: Tue, 9 Sep 2003 09:30:57 +0100 |
> But I want to take this one step further and return the count > of all nodes > that have a position() that is less than the position of the > current node. > Taking the position() of the context node out of the equation > I thought it > would as simple as this (I used 5 as a test parameter)... Nodes do not "have a position()". The result of the position() function is context dependent: it returns the position of the current node in the current node list, and the current node list depends on how you reached the node in your processing. I suspect that you are using "the position of a node" to mean something like "the number of preceding siblings of the node", which is count(preceding-sibling::node()). Michael Kay > > <xsl:key name="linkCount" match="lid[position() < 5]" use="."/> > > I expected it to return the count of the nodes that matched > the current > context node as long as there postion was less than 5. But > it didn't. It > returned the total count for the entire xml tree. > > So, my questions are... 1)What do I need to change to get > the above example > to work and 2)How could I then take it one step further and use the > position() of the current context node as the parameter to > test against the > position() of the test nodes? > > Your help is much appreciated! > > Best Regards, > > M.David > > XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list > XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list
Current Thread |
---|
|
<- Previous | Index | Next -> |
---|---|---|
[xsl] limit count() to nodes with a, M. David Peterson | Thread | Re: [xsl] limit count() to nodes wi, M. David Peterson |
Re: [xsl] sum() with decimal-separa, M. David Peterson | Date | Re: [xsl] sum() with decimal-separa, M. David Peterson |
Month |