[xsl] Count() nodes ??

Subject: [xsl] Count() nodes ??
From: Dipesh Khakhkhar <dkhakhkh@xxxxxxxxxxxxxxx>
Date: Tue, 16 Sep 2003 11:24:21 -0400
Hi,

I am having the following xml document.

<Root>
 <FixedNodes>
   <Node name="1">
      <Subnode myAtt="itsValue"/>
      <Subnode myAtt="itsValue"/>
      <Subnode myAtt="itsValue"/>
   </Node>
   <Node name="2">
       <Subnode myAtt="itsValue">
       <Subnode myAtt="itsValue">
       <Subnode myAtt="itsValue">
       <Subnode myAtt="itsValue">
    </Node>
 </FixedNodes>
 <VaryingNodes>
     <Node name="3">
       <Subnode myAtt="itsValue">
       <Subnode myAtt="itsValue">
     </Node>
  </VaryingNodes>
</Root>

How do i count number of Subnode within FixedNodes.
I tried using
 "count(//Root/FixedNodes/Node/Subnode)
But i got count as zero. Is this because there is attribute associated with 
each of the Node element ?

Can someone please tell me how do i count it ?
Thanks in the anticipation that I will get some reply.

Regards,
Dipesh


 XSL-List info and archive:  http://www.mulberrytech.com/xsl/xsl-list


Current Thread