[xsl] Find position of a node with id attribute

["Robert Ogden" <Robert.Ogden@xxxxxxxx>]

Trying to find the position of a node with an attribute id for a href
target

so...code:

<xsl:template match="xref">
   <xsl:variable name="anchor" select="@xrefid"/>
   <xsl:variable name="file">
      <xsl:for-each select="document('a.xml')">
         <xsl:for-each select="//*[@id='$anchor']">
            <!-- Find position of node relative chapter, section,
and/or para0 elements -->
            <!-- Example node resides within 1st chapter, 2nd section,
and 0th para0 element, result would be 1-2-0 -->
            <xsl:number format="1-1-1" level="multiple" count="chapter
|  section | para0"/>
         </xsl:for-each>
      </xsl:for-each>
   </xsl:variable>
   <xsl:variable name="file_num" select="concat('chap', $file,
'.html')"/>
   <!-- For same example as above, result would be chap1-2-0.html#[the
value of $anchor] -->
   <a href="{$file_num}#{$anchor}">
      <xsl:value-of select="$file_num"/>#<xsl:value-of
select="$anchor"/>
   </a>
</xsl:template>

Thanks for any help/ideas

-Robert


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