RE: [xsl] Replacing double quotes with XSLT

Subject: RE: [xsl] Replacing double quotes with XSLT
From: "Koes, Derrick" <Derrick.Koes@xxxxxxxxxxxxxxxx>
Date: Mon, 22 Sep 2003 18:01:51 -0400
Recursive template to do what you need.

<xsl:template name="escapeQuot">
    <xsl:param name="text"/>
      <xsl:when test="contains($text, '&quot;')">
        <xsl:variable name="bufferBefore" select="substring-before($text,
        <xsl:variable name="newBuffer" select="substring-after($text,
        <xsl:value-of select="$bufferBefore"/><xsl:text>\"</xsl:text>
        <xsl:call-template name="escapeQuot">
          <xsl:with-param name="text" select="$newBuffer"/>
        <xsl:value-of select="$text"/>

-----Original Message-----
From: Andreas L. Delmelle [mailto:a_l.delmelle@xxxxxxxxxx] 
Sent: Monday, September 22, 2003 5:43 PM
To: xsl-list@xxxxxxxxxxxxxxxxxxxxxx
Subject: RE: [xsl] Replacing double quotes with XSLT

> -----Original Message-----
> From James Paul
> Even when trying to replace with the " with a single character it does
> not work.
> Example
>  <xsl:element name = "OrganizationCode">
>  	<xsl:text>"</xsl:text>
>  	<xsl:value-of select =
>  "translate(../@OrganizationCode,'\"','B'"/>
>  	<xsl:text>"</xsl:text>
>  </xsl:element>

Question: Is this an *exact* copy of what you put in the stylesheet? 
If so, I see a closing bracket missing... (wild guess)


Andreas Delmelle

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