RE: [xsl] How to open a page in xsl

Subject: RE: [xsl] How to open a page in xsl
From: "Jim Fuller" <jim.fuller@xxxxxxxxxxxxxxxxxx>
Date: Tue, 23 Sep 2003 09:14:41 +0100
a sample src xml and desired xml may reveal what you want to do, possibly

you want a choose statement

	<xsl:when test="contain($username,'yahoo')">
		do something
		do something by default

not sure at all what you want to do ?

gl, jim fuller

-----Original Message-----
From: Archana Rao [mailto:archana_heroor@xxxxxxxxx]
Sent: 22 September 2003 22:41
To: xsl-list@xxxxxxxxxxxxxxxxxxxxxx
Subject: [xsl] How to open a page in xsl

Hello everybody,

JSP passes the username to my xsl, i know what the
user name is that is, in my xsl i have <xsl:param

So i know what the username is, now my problem is i am
trying to open up if the username is
xyz@xxxxxxxxx and if the username has

I know i can use <xsl:if test="contain($username,
'yahoo')"> to check for the username, but then i don't
know how to specify in the <xsl:if> to open up

Hope you understood my problem.


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