Subject: [xsl] Re: Current Date and Time From: "Dimitre Novatchev" <dnovatchev@xxxxxxxxx> Date: Tue, 23 Sep 2003 22:37:34 +0200 |
FAQ: Pass the date and time as a parameter to the transformation -- read your XSLT processor documentation for details, as such passing of parameters is vendor-specific. ===== Cheers, Dimitre Novatchev. http://fxsl.sourceforge.net/ -- the home of FXSL "James Paul" <jpaul@xxxxxxxxxxx> wrote in message news:F78AE312483A2A46B76BF4D2D4842A650294AB61@xxxxxxxxxxxxxxxxxxxxxxxx > Is there an easy way to get the current date and time in XSLT? If not > how could you do this. > > Thanks, > James Paul > > XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list > > XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list
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