RE: [xsl] Multiple input files

["Martinez, Brian" <brian.martinez@xxxxxxxxxxx>]

> From: Ricardo Saraiva [mailto:rss@xxxxxxxxxxxxxx]
> Sent: Thursday, September 25, 2003 8:46 AM
> Subject: [xsl] Multiple input files
> 
> 
> My question is how to read all the xml files in one directory as input
> files to my XSL file?

The document() function does not provide for using wildcards to resolve
URIs, so it's not possible to fully automate the process by doing something
like

<xsl:apply-templates select="document('*.xml')"/>

One solution is to create an XML source document listing all the files you
want to process, then use it as the input for the stylesheet.  Given source
such as:

<file-list>
  <file>a.xml</file>
  <file>b.xml</file>
  <!-- etc. -->
</file-list>

you can do something like this:

<xsl:template match="/file-list">
  <xsl:for-each select="document(file)">
    <!-- do something -->
  </xsl:for-each>
</xsl:template>

This is expensive, as it selects the root node (in other words, the entire
document) as the context for each iteration--see the FAQ
(http://www.dpawson.co.uk/xsl/sect2/N2602.html#d2874e403) for more ideas on
processing multiple documents.

hth,
b.

| brian martinez                           brian.martinez@xxxxxxxxxxx |
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