Subject: RE: [xsl] [position node] I to get it. From: Lionel Crine <crine@xxxxxxxxxxxx> Date: Wed, 01 Oct 2003 15:40:29 +0200 |
if you match the child document from the parent document you can define a parameterized template and call it like this:
<xsl:apply-templates select="dmidref"> <xsl:with-param name="parentposition" select="position()"/> </xsl:apply-templates>
and the template for the child must look like this:
<xsl:template match="dmidref"> <xsl:param name="parentposition"/> <!-- something --> <xsl:value-of select="$parentposition"/> <!-- something --> </xsl:template>
Sergiu > -----Original Message----- > From: Lionel Crine [mailto:crine@xxxxxxxxxxxx] > Sent: 1 octombrie 2003 11:35 > To: XSL-List@xxxxxxxxxxxxxxxxxxxxxx > Subject: [xsl] [position node] I to get it. > > > Hello, > > Id' like to get the position of the parent node of the context node : > > For example : > > <dmref> > <dmidref> --> from here I need the position of dmref > <dmidref> > > Is it possible ? > > Lionel > > Lionel CRINE > Ingénieur Systèmes documentaires > Société : 4DConcept > 22 rue Etienne de Jouy 78353 JOUY EN JOSAS > Tel : 01.34.58.70.70 Fax : 01.39.58.70.70 > > > XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list > >
XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list
Lionel CRINE Ingénieur Systèmes documentaires Société : 4DConcept 22 rue Etienne de Jouy 78353 JOUY EN JOSAS Tel : 01.34.58.70.70 Fax : 01.39.58.70.70
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