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Subject: [xsl] linefeed to <br/> template From: Flemming Jønsson <flj@xxxxxxxxxxxxx> Date: Tue, 7 Oct 2003 17:10:00 +0200 |
Hi!,
I have som XML files from which I need to generate som HTML.
Part of my XML is source code (or rather named queries in SQL) and I need to pretty-print these in some HTML tables.
I want to replace newlines with a <br/> - I found a template to do just that at www.skew.org/xml (Thanks Mark :)- but I have som problems I hope you can help me weed out.
I use Xalan as XSLT processor, in case that changes anything.
Here is the template:
<xsl:template name="lf2br">
<xsl:param name="StringToTransform"/>
<xsl:choose>
<xsl:when test="contains($StringToTransform,' ')">
<xsl:value-of select="substring-before($StringToTransform,' ')"/>
<br/>
<xsl:call-template name="lf2br">
<xsl:with-param name="StringToTransform" select="substring-after($StringToTransform,' ')"/>
</xsl:call-template>
</xsl:when>
<xsl:otherwise>
<xsl:value-of select="$StringToTransform"/>
</xsl:otherwise>
</xsl:choose>
</xsl:template>
I want to use this call to remove newlines in a string - and store the result in a variable named sqlExample
<xsl:variable name="sqlExample">
<xsl:call-template name="lf2br">
<xsl:with-param name="StringToTransform" select="SQL/text()" />
</xsl:call-template>
</xsl:variable>
This does not work, however.
$sqlExample contains the text, but there are no <br> in it?
If I remove the <xsl:variable> surrounding the call-template part, it works just fine - the <br> tags are in the printed output as expected.
How come, it works when I print the output, but not when I store it in a variable?
I really would like to put the results in a variable, since I need to do some further processing on it - but is this not possible, without loosing the formatting?
Thank you for your help.
Regards,
Flemming Joensson
XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list
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