Re: [xsl] looping problem, <xsl: for-each>??

Subject: Re: [xsl] looping problem, <xsl: for-each>??
From: Wendell Piez <wapiez@xxxxxxxxxxxxxxxx>
Date: Tue, 07 Oct 2003 15:39:23 -0400
At 01:08 PM 10/7/2003, Mukul wrote:
Hi James,
 This is a grouping problem, which can be solved by
the Muenchian method. Please try the following XSL --

<?xml version="1.0" encoding="UTF-8"?>
<xsl:stylesheet version="1.0"
xmlns:xsl="http://www.w3.org/1999/XSL/Transform";>
   <xsl:output method="xml" version="1.0"
encoding="UTF-8" indent="yes"/>
   <xsl:key name="x" match="/rss/channel/item"
use="category" />

    <xsl:template match="/">
      <xsl:for-each select="rss/channel/item">
        <xsl:if test="generate-id(.) = generate-id(key('x',
category)[1])">
         <h1>
            <xsl:value-of select="category" />
         </h1>
        <xsl:for-each select="key('x', category)">
ITEM<!-- ?? -->  <xsl:value-of select="description"/>
        </xsl:for-each>
       </xsl:if>
     </xsl:for-each>
   </xsl:template>

</xsl:stylesheet>

You want the labels to be output as -- ITEM1, ITEM2,
ITEM3, ITEM 4. I cannot think of a good way to do
this. <!-- ?? --> part of my XSL needs to be
completed.

Something using position() and count() should be
required..

In the general case, two passes, or a resort to a node-set extension function, is necessary for a clean solution to this, because the numbering depends not on the order and position of nodes in the source document, but in the result.


When we are not reordering the nodes within their groups, however, one can often force this ...

<xsl:value-of select="count(preceding::item[category=current()/category])+1"/>

but be warned: it can be slowish to execute on large documents.

No variable reassignment is called for here.

Cheers,
Wendell

James's spec:

I have the following format but am having trouble trying to group items (in html) under one common category so that it isnt repeated for every item but can act as a title:
<rss version="0.92">
- <channel>
- <item>
<title>title here</title>
<category>Top Stories</category>
<link>http</link>
<description>text is heredescription>
</item>
</channel>
<item>
<title>title here</title>
<category>top stories</category>
<link>http</link>
<description>text is heredescription>
</item>
</channel>
<item>
<title>title here</title>
<category>Stories today</category>
<link>http</link>
<description>text is heredescription>
</item>
</channel>
<item>
<title>title here</title>
<category>Stories today</category>
<link>http</link>
<description>text is heredescription>
</item>
</channel>
</rss>


e.g. the final look i wanted to create was:
<h1>top stories </h1>
ITEM1 <xsl:value-of select="description">
ITEM2 <xsl:value-of select="description">
<h1>stories today</h1>
ITEM3 <xsl:value-of select="description">
ITEM4 <xsl:value-of select="description">



====================================================================== Wendell Piez mailto:wapiez@xxxxxxxxxxxxxxxx Mulberry Technologies, Inc. http://www.mulberrytech.com 17 West Jefferson Street Direct Phone: 301/315-9635 Suite 207 Phone: 301/315-9631 Rockville, MD 20850 Fax: 301/315-8285 ---------------------------------------------------------------------- Mulberry Technologies: A Consultancy Specializing in SGML and XML ======================================================================


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