Subject: [xsl] Regarding xsl transformation to xml tree From: "Chadha, Devesh" <devesh.chadha@xxxxxxxxxx> Date: Wed, 8 Oct 2003 15:41:07 -0400 |
Hi, I am in a quandary. I have a huge xml tree that has the following structure- <all_plants> <plant> maple <type>tree</tree> <height>tall</height> </plant> <plant> dandelion <type>weed</tree> <height>short</height> </plant> <plant> sage <type>herb</tree> <height>short</height> </plant> </all_plants> I need the xsl that would give me a result as: Maple Dandelion Sage Here is the XSL transform I am using <xsl:template match="/"> <html> <body> <xsl:apply-templates select="all_plants"> </body> </html> </xsl:template> <xsl:template match="all_plants"> <table> <xsl:apply-templates select="plant"> </table> </xsl:apply-templates> <xsl:template match="plant"> <tr><td><value-of select="."/></td></tr> </xsl:template> ....let me know what I am doing wrong!! Is there any other way I can do this????? Any help would be greatly appreciated... Regards, DC ------------------------------------------------------------------------------ This message is intended only for the personal and confidential use of the designated recipient(s) named above. If you are not the intended recipient of this message you are hereby notified that any review, dissemination, distribution or copying of this message is strictly prohibited. This communication is for information purposes only and should not be regarded as an offer to sell or as a solicitation of an offer to buy any financial product, an official confirmation of any transaction, or as an official statement of Lehman Brothers. Email transmission cannot be guaranteed to be secure or error-free. Therefore, we do not represent that this information is complete or accurate and it should not be relied upon as such. All information is subject to change without notice. XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list
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