Subject: RE: [xsl] generate XHTML header without causing xmlns attributes in e.g. <table>? From: Flemming Jønsson <flj@xxxxxxxxxxxxx> Date: Fri, 17 Oct 2003 14:38:10 +0200 |
Hi Jarkko, > > I thought I had to declare the name space in the xsl:template line > > like this: > > > > <xsl:template name="exparameters" match="EX_PARAMETERS" > xml:space="preserve" xmlns="http://www.w3.org/1999/xhtml" > xmlns:fo="http://www.w3.org/1999/XSL/Format"> > > <table border="1" cellpadding="3" cellspacing="0" > class="parameters" > > > <thead> > > <tr> > > ... > > > > Well, normally these kind of declarations are done in the > stylesheet level. > Originally I did it the way you suggests: I have removed the xml namespace declaration in the template def. and tried this: <xsl:stylesheet version="1.0" xmlns="http://www.w3.org/1999/xhtml" xmlns:xsl="http://www.w3.org/1999/XSL/Transform"> However I get that xmlns="" in my table anyway? The funny part is, I have two <table> tags in the page which is generated, and it is only in the second one that gets the xmlns attribute - why is that? The template declarations look like this (now): <xsl:template name="query" match="QUERY"> And <xsl:template name="exparameters" match="EX_PARAMETERS" xml:space="preserve"> First table tag in generated xhtml looks like this <table class="querydef" cellspacing="0" cellpadding="3" border="1"> Second table tag looks like this <table xmlns="" class="parameters" cellspacing="0" cellpadding="3" border="1"> I have tried searching the web for answers, but I don't think I've used the right keywords - I haven't been able to find anything which could lead me towards a solution to this. I am a beginner, so it might be even the simplest thing I've missed - so any help will be appreciated. Have a great weekend everyone, Flemming XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list
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