Subject: [xsl] RE: XPath: selecting matching nodes in two node-sets From: Richard Lewis <richard.lewis@xxxxxxxxx> Date: Mon, 20 Oct 2003 19:35:26 +0100 |
Thanks for the ideas. It seems I probably haven't made myself clear! The project I'm working on is a record library. The top-level method is: 'library.xml' --> --> 'simple-search.xsl' --> [select 'items' which contain ANY of the keywords] --> --> 'results.xml' --> --> 'display-results.xsl' --> [select 'items' which contain ALL of the keywords] --> --> HTML output The the 'results.xml' document contains a single 'keywords' node: <keywords> <matches>song</matches> <matches>medieval</matches> </keywords> and any number of 'item' nodes: <item> <id>CD106</id> <title>Medieval English Song</title> <publisher>Hyperion</publisher> <date_published>1998</date_published> <matches>song</matches> <matches>medieval</matches> <matches>song</matches> <matches>song</matches> <matches>medieval</matches> <matches>song</matches> </item> <item> <id>CD258</id> <title>Kevin Volans Songline Quartets</title> <publisher>Naxos</publisher> <date_published>2003</date_published> <matches>song</matches> <matches>song</matches> </item> (Note: the 'item' nodes in 'library.xml' contain a lot more data) So what I need is a XPath expression which says: select 'items' where every 'keywords/matches' is present in './matches'. so I tried: "//item[matches = //keywords/matches]" but this returned 'items' where any keywords matched. I think thats it. Thanks for your help so far and in advance for any further ideas! Cheers, Richard XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list
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