Subject: [xsl] Re: newline [\n] to <br /> From: "scott" <scott@xxxxxxxxxxxxxxxx> Date: Fri, 24 Oct 2003 01:06:17 +0100 |
Duh...i got it :) <xsl:call-template name="break"> <xsl:with-param name="text"> <xsl:value-of select="body"/> </xsl:with-param> </xsl:call-template> The faq needs to be a bit clearer for idiots like me .... What the heck is : <xsl:template match="text()"> <xsl:call-template name="break"> </xsl:template> That about then??? Still after recommendations for books though please. -----Original Message----- From: scott [mailto:scott@xxxxxxxxxxxxxxxx] Sent: 23 October 2003 23:51 To: 'XSL-List@xxxxxxxxxxxxxxxxxxxxxx' Subject: newline [\n] to <br /> Im very new to this, so apologies for what I know must be a dumb question, but i can't find anything solid anywhere; I've looked at the faq but I cant get it working. I need to replace \n newlines in some output from a MySQL db - ive tried doing this in php (wrong idea I guess) before passing to the parser, but that doesn't work. So I find this: code from faq [replace]... <xsl:template match="text()"> <xsl:call-template name="break"> </xsl:template> <xsl:template name="break"> <xsl:param name="text" select="."/> <xsl:choose> <xsl:when test="contains($text, '
')"> <xsl:value-of select="substring-before($text, '
')"/> <br/> <xsl:call-template name="break"> <xsl:with-param name="text" select="substring-after($text, '
')"/> </xsl:call-template> </xsl:when> <xsl:otherwise> <xsl:value-of select="$text"/> </xsl:otherwise> </xsl:choose> </xsl:template> my (simple!) stylesheet ... <xsl:template match="/"> /* more html / xsl:value-of's here... <p> <xsl:value-of select="body"/> </p> <xsl:if test="links"> <ul> <xsl:for-each select="links/url"> <li> <xsl:element name="a"> <xsl:attribute name="href"> <xsl:value-of select="location"/> </xsl:attribute> <xsl:value-of select="text"/> </xsl:element> <xsl:value-of select="comment"/> </li> </xsl:for-each> </ul> </xsl:if> /* more html / xsl:value-of's here... </xsl:template> this :: <xsl:value-of select="body"/> :: is what I want to parse for newlines and replace with html breaks on output(outputting to xhtml); ive tried dropping the template in to replace the above line, using part of it (the choose etc), adding the template outside the existing one.... I can't get it to work, and I cant find any info on the web that isn't either completely basic, or over my head at this stage. Please, how do I USE this template with regards to an existing one?? Any recommendations for books would be appreciated too. thanks scott mathieson XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list
Current Thread |
---|
|
<- Previous | Index | Next -> |
---|---|---|
Re: [xsl] newline [\n] to <br />, David Carlisle | Thread | [xsl] position() returns what?, Morten Andersen |
[xsl] newline [\n] to <br />, Mulberry Technologie | Date | [xsl] position() returns what?, Morten Andersen |
Month |