Re: [xsl] Finding topmost element of a nested, nested list

[David Carlisle <davidc@xxxxxxxxx>]

level.xml:
<chapter>1.
  <level>I.
    <level>A.
      <section>1</section>
      <section>2</section>
    </level>
    <level>B.
      <section>3
        <image/>
      </section>
    </level>
  </level>
  <level>II.
    <level>A.
      <section>4</section>
    </level>
    <level>B.
      <section>5
        <image/>
      </section>
    </level>
  </level>
  <level>III.
    <level>A.
      <section>6
        <image/>
      </section>
    </level>
  </level>
</chapter>


level.xsl:


<xsl:stylesheet xmlns:xsl="http://www.w3.org/1999/XSL/Transform"; version="1.0">

<xsl:template match="*">
<xsl:copy>
<xsl:apply-templates/>
</xsl:copy>
</xsl:template>

<xsl:template match="*" mode="x">
<xsl:apply-templates select="*[1]" mode="x"/>
</xsl:template>

<xsl:template match="image" mode="x">.</xsl:template>

<xsl:template match="level">
<xsl:variable name="x">
  <xsl:apply-templates mode="x" select="."/>
</xsl:variable>
<xsl:variable name="y">
  <xsl:apply-templates mode="x" select=".."/>
</xsl:variable>
<xsl:if test="string($x) and not(string($y))">
<xsl:comment>end page here</xsl:comment>
<xsl:text>&#10;</xsl:text>
</xsl:if>
<xsl:copy>
<xsl:apply-templates/>
</xsl:copy>
</xsl:template>

</xsl:stylesheet>

$ saxon level.xml level.xsl
<?xml version="1.0" encoding="utf-8"?><chapter>1.
  <level>I.
    <level>A.
      <section>1</section>
      <section>2</section>
    </level>
    <!--end page here-->
<level>B.
      <section>3
        <image/>
      </section>
    </level>
  </level>
  <level>II.
    <level>A.
      <section>4</section>
    </level>
    <!--end page here-->
<level>B.
      <section>5
        <image/>
      </section>
    </level>
  </level>
  <!--end page here-->
<level>III.
    <level>A.
      <section>6
        <image/>
      </section>
    </level>
  </level>
</chapter>


-- 
http://www.dcarlisle.demon.co.uk/matthew

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