RE: [xsl] Handling Duplicate Lines in XSL

Subject: RE: [xsl] Handling Duplicate Lines in XSL
From: "Murali Korrapati" <murali.korrapati@xxxxxxxxx>
Date: Fri, 31 Oct 2003 15:40:40 -0500

    Sorry for not being clear on what it was doing. I was getting output as 

Cust1 443 West
Cust1 443 East
Cust1 443 East
Cust1 443 West

that means it is returning all the values without suppressing the duplicate values

I tried with your suggestion, but still getting the same result.

thanks for your help.


-----Original Message-----
From: J.Pietschmann [mailto:j3322ptm@xxxxxxxx]
Sent: Friday, October 31, 2003 3:06 PM
To: xsl-list@xxxxxxxxxxxxxxxxxxxxxx
Subject: Re: [xsl] Handling Duplicate Lines in XSL

Murali Korrapati wrote:
> But I have a slightly different problem though.
> <xsl:for-each select="root[not(foo/bar = preceding-sibling::foo/bar)]">
>     <xsl:value-of select="."/><br/>
> </xsl:for-each>

You probably want to select the foo instead of the root element:
  <xsl:for-each select="root/foo[not(bar = ../preceding-sibling::foo/bar)]">

> but, it doesn't seem like working. 
Well, there are many ways to "not work". You should be
more specific, for example "no output" or "I got this
output ..."


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