Subject: Re: [xsl] Re: Excluding one particular attribute(namespace) when copying elements From: Dongling Ding <dling61@xxxxxxxxx> Date: Fri, 31 Oct 2003 15:38:01 -0800 (PST) |
Hi Dimitre, This one is working. But I found out another interesting thing here and i think it may need people attention. Here is xml, xslt and output test1.xml <D xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"> <x>1</x> <y>2</y> <z>3</z> </D> test1.xslt: <xsl:template match="D"> <D> <xsl:if test="./*[name(.) = 'x']"> <xsl:copy-of select="./*[name(.) = 'x']"/> </xsl:if> </D> </xsl:template> Output: <D> <x xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance">1</x> </D> My question is: Why the "xmlna:xsi......." was inserted in the element x here? Any anwser? Thanks Dongling --- Dimitre Novatchev <dnovatchev@xxxxxxxxx> wrote: > > I need to copy different element to output. For > all > > the elements I need to exclude the namespace > attribute > > when i use "xsl:copy-of" or "xsl:copy". It seems > > difficult to specify this in XSLT. Any comment > would > > be appreciated! > > Use something like this: > > <xsl:stylesheet version="1.0" > xmlns:xsl="http://www.w3.org/1999/XSL/Transform"> > <xsl:output omit-xml-declaration="yes"/> > > <xsl:template match="t"> > <xsl:element name="{name()}"> > <xsl:copy-of select="namespace::*[not(. = > 'b')]"/> > <xsl:copy-of select="@* | node()"/> > </xsl:element> > </xsl:template> > </xsl:stylesheet> > > When this transformation is applied on the following > source.xml: > > <t xmlns:a="a" xmlns:b="b"/> > > the result is: > > <t xmlns:a="a"/> > > so the namespace "b" has been excluded. > > > Hope this helped. > > > ===== > Cheers, > > Dimitre Novatchev. > http://fxsl.sourceforge.net/ -- the home of FXSL > > > > > XSL-List info and archive: > http://www.mulberrytech.com/xsl/xsl-list > __________________________________ Do you Yahoo!? Exclusive Video Premiere - Britney Spears http://launch.yahoo.com/promos/britneyspears/ XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list
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