<-prev [Thread] next-> <-prev [Date] next->
Month Index | List Home

RE: [xsl] How to unflatten the source XML ?

Subject: RE: [xsl] How to unflatten the source XML ?
From: Jarno.Elovirta@xxxxxxxxx
Date: Thu, 6 Nov 2003 08:51:14 +0200
Hi,

> Would you please tell me how to group fixed number (say 3) of 
> consecutive node together?

  <xsl:template match="*[item]">
    <xsl:for-each select="item[position() mod 3 = 1]">
      <group id="{position()}">
        <xsl:copy-of select=". | following-sibling::item[position() &lt; 3]"/>
      </group>
    </xsl:for-each>
  </xsl:template>

Cheers,

Jarno - Project Pitchfork: Carrion

 XSL-List info and archive:  http://www.mulberrytech.com/xsl/xsl-list
Current Thread
<- PreviousIndexNext ->
[xsl] How to unflatten the source X, Herman Kwok Thread [xsl] problem endless rekursion, Markus Hanel
[xsl] How to unflatten the source X, Herman Kwok Date [xsl] problem endless rekursion, Markus Hanel
Month