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Subject: Re: [xsl] Can not convert #STRING to a NodeList! Error.. From: Mukul Gandhi <mukulgw3@xxxxxxxxx> Date: Sat, 8 Nov 2003 10:57:34 -0800 (PST) |
I guess, there is some problem with the way, you are
using/accessing xsl:key definition. Can you please
post the xsl:key definition, the source XML, and the
desired output?
I have experianced, that the error message "can not
convert #STRING to a NodeList" comes, when a value of
type *NodeList* was expected, and a *string value* is
provided in its place..
Regards,
Mukul
--- arun prasath <arunwaits@xxxxxxxxxxx> wrote:
> Hi,
> In my XSL,
> from the parent template I load a XML file using
> document() function. and I
> pass this as parameter to child templates.
> <xsl:call-template name="main">
> <xsl:with-param name="labelsfile"
> select="document('English.xml')"/>
> </xsl:call-template>
>
> In my child templates, I am retrieving using
> <xsl:param name="labelsfile"/>
>
> I also have declared a key(xsl:key) in the importing
> xml file in my xsl.
> <xsl:for-each select="$labelsfile">
> <xsl:value-of
> select="key('label','ecollab.businessfollowedby')"
> />
> </xsl:for-each>
>
> when I transform this using my java program, I get
> the following exception.
> Can not convert #STRING to a NodeList!
>
> I want to know why we get this error usually.
> please help
> regards
> s.arun prasath
>
>
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