Subject: [xsl] Re: Re: Re: Re: Sibling in the Pattern(match) From: "Dimitre Novatchev" <dnovatchev@xxxxxxxxx> Date: Tue, 25 Nov 2003 20:13:06 +0100 |
> However, "Member[@name > ='acc1']/Member[@name='acc11']]" seems not okay in the > match. It only recognized the "Member[@name='acc1'], > not the full path. Not true! Probably you are using some buggy XSLT processor? Here's the very simple xslt code: <xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform"> <xsl:output omit-xml-declaration="yes"/> <xsl:template match="@* | node()"> <xsl:copy> <xsl:apply-templates select="@* | node()"/> </xsl:copy> </xsl:template> <xsl:template match="Member[@name='acc1']/Member[@name='acc11']"/> </xsl:stylesheet> when applied on your source.xml: <D> <Member comment="" name="acc1"> <Calc>+</Calc> <Member comment="" name="acc11"> <Calc>+</Calc> <Member name="account3_1"/> </Member> <Member comment="" name="acc12"> <Calc>+</Calc> <Member name="acc121"/> </Member> </Member> <Member comment="" name="acc2"> <Calc>+</Calc> </Member> <Member comment="" name="acc3"> <Calc>+</Calc> <Member comment="" name="acc31"> <Calc>+</Calc> </Member> <Member comment="" name="acc11"> <Calc>+</Calc> </Member> </Member> </D> the wanted result is produced: <D> <Member comment="" name="acc1"> <Calc>+</Calc> <Member comment="" name="acc12"> <Calc>+</Calc> <Member name="acc121"></Member> </Member> </Member> <Member comment="" name="acc2"> <Calc>+</Calc> </Member> <Member comment="" name="acc3"> <Calc>+</Calc> <Member comment="" name="acc31"> <Calc>+</Calc> </Member> <Member comment="" name="acc11"> <Calc>+</Calc> </Member> </Member> </D> As you can see, the first "Member" withname="acc11" is removed, but the second is in the result tree. I tested this with all 8 different XSLT 1.0 processors I have installed -- all produced exactly the same result. ===== Cheers, Dimitre Novatchev. http://fxsl.sourceforge.net/ -- the home of FXSL XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list
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