[xsl] HOWTO: convert flat list w/ level information to a hierarchial one?

Subject: [xsl] HOWTO: convert flat list w/ level information to a hierarchial one?
From: "Marcus Zelezny" <Marcus.Zelezny@xxxxxx>
Date: Tue, 2 Dec 2003 11:40:58 +0100
Dear XSLT Community!

I couldn't solve a problem of class "flat file transform".

>From (@name, just for illustration) flat file with @level information:
 <node level="0" type="c" name="toplevel"/>
 <node level="1" type="i" name="1. item"/>
 <node level="1" type="c" name="2. container"/>
 <node level="2" type="i" name="2.1 item"/>
 <node level="2" type="i" name="2.2 item"/>
 <node level="1" type="i" name="3. item"/><!-- implicit close of previous container -->
 <node level="1" type="c" name="4. container"/>
 <node level="2" type="i" name="4.1 item"/>
 <node level="2" type="c" name="4.2 container"/>
 <node level="3" type="i" name="4.2.1 item"/>
@type = 'c' ... container
@type = 'i' ... Item

transform to:
 <node type="c" name="toplevel">
  <node type="i" name="1. item"/>
  <node type="c" name="2. container"/>
   <node type="i" name="2.1 item"/>
   <node type="i" name="2.2 item"/>
  <node type="i" name="3. item"/>
  <node type="c" name="4. container">
   <node type="i" name="4.1 item"/>
   <node type="c" name="4.2 container"/>
    <node type="i" name="4.2.1 item"/>

What I tried:
Calling recursively a template with passing parameters $node, $last-level, but I failed to leave recursion in a proper way;-(

Any pointer|hint|solution for a (ideally) XSLT1.0 approach is highly appreciated!

Thanks in advance

P.S. I read http://www.dpawson.co.uk/xsl/sect2/flatfile.html

 XSL-List info and archive:  http://www.mulberrytech.com/xsl/xsl-list

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