RE: [xsl] Easy way to identify node type?

Subject: RE: [xsl] Easy way to identify node type?
From: Haydn Flower <Haydn.Flower@xxxxxxxxxxx>
Date: Thu, 4 Dec 2003 16:31:57 -0000
Yes, You've gotta use an XPath type statement which use expressions (kind of
similar to perl expressions but different),
give an example of your input xml and which elements you want matched.

-----Original Message-----
From: yguaba@xxxxxxxxxxxx [mailto:yguaba@xxxxxxxxxxxx]
Sent: 04 December 2003 16:23
To: xsl-list@xxxxxxxxxxxxxxxxxxxxxx
Subject: [xsl] Easy way to identify node type?


Is there an easy way (or any way at all) to identify the type of the  
node being processed? Suppose, for instance, that you wanted to 
produce different output for different node types, as in the 
*fictitious* example below:

<xsl:template match="root">
	<xsl:for-each select="node()">
		<xsl:choose>
			<xsl:when test="node-type() = 'ELEMENT'">
				<xsl:text>blah, blah</xsl:text>
			</xsl:when>
			<xsl:when test="node-type() = 'TEXT'">
				<xsl:value-of select="."/>
			</xsl:when>
			...
		</xsl:choose>
	</xsl:for-each>
</xsl:template>

Is there a way to do that?

Thanks in advance for your input,

Erik

 XSL-List info and archive:  http://www.mulberrytech.com/xsl/xsl-list


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