Re: [xsl] XPATH | union operator question

[Marc Liyanage <liyanage@xxxxxxxxx>]

On 21.12.2003, at 14:24, Andreas L. Delmelle wrote:

> Hi Marc,
>
>
> Perhaps Mike Kay's answer earlier on in this thread could be the 
> solution :
>
> <xsl:value-of select="(thing[lang($mylang)] | thing)[last()] />

I read that, but I guess that's useful for the original problem, where 
you have a hierarchy, i.e. you have an outermost and an innermost node 
to select. In that case, the last() will make sure you get the 
innermost node.

In my case, the elements are on the same level so that can't be used.


> either that or change your input doc to :

Unfortunately I have no control over the input docs in this particular 
application.


The solution proposed by Dimitre Novatchev earlier today works very 
well for me.






_________________________________________________________________
Marc Liyanage                                     marc@xxxxxxxxxx
                                            http://www.entropy.ch
                                          iChat: liyanage@xxxxxxx

                                      Yoda I am. Grammar I can't.
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