RE: [xsl] Getting rid of xmlns="" attributes

Subject: RE: [xsl] Getting rid of xmlns="" attributes
From: "Michael Kay" <mhk@xxxxxxxxx>
Date: Wed, 31 Dec 2003 18:04:36 -0000
The system has inserted an xmlns="" namespace declaration because you
have asked for the <exportTimeStamp> element to go in the null
namespace. If you don't want this namespace declaration, then presumably
you actually want the exportTimeStamp element to be in the namespace However, you are producing this
element as a copy of an element in the source document, and presumably
the element in the source document was in the null namespace. When you
copy an element from the source document, you can't change its namespace
- copy really does mean "copy exactly". If you want to change the
namespace of an element, use <xsl:element name="{local-name()}"

Remember that you control, from the stylesheet, the namespace in which
new elements are created. The serializer then produces namespace
declarations to reflect this. Usually, if you aren't happy with the
namespace declarations in the output, it's because you are creating
elements in the wrong namespace.

Michael Kay

> -----Original Message-----
> From: owner-xsl-list@xxxxxxxxxxxxxxxxxxxxxx 
> [mailto:owner-xsl-list@xxxxxxxxxxxxxxxxxxxxxx] On Behalf Of 
> Allen, Erik
> Sent: 30 December 2003 23:23
> To: XSL-List@xxxxxxxxxxxxxxxxxxxxxx
> Subject: [xsl] Getting rid of xmlns="" attributes
> 	I've been using XSL for a few months now and I've been 
> given a request for a transformation of our XML document into 
> another XML document, with only some slight changes. One of 
> the changes is to remove a xml:space="preserve" attribute, 
> but I consider that a trivial problem that I can easily 
> solve. (I'm just explicitly writing the element with the two 
> other attributes that appear.) The bigger problem is that I 
> need to add two namespaces to the XML.
> 	From what I've read on this list, the best place to do 
> something like that is to place the namespace definitions 
> within the <xsl:stylesheet> element. I've done that, but now 
> all the child elements have xmlns="" appearing within them. 
> My XSL looks like this:
> <?xml version="1.0" encoding="iso-8859-1"?>
> <xsl:stylesheet xmlns:xsl=''
> 			xmlns="";
> xmlns:xsi="";
> 			version = '1.0'>
> <xsl:output method="xml"/>
> <xsl:template match="/template">
> 	<template>
> 		<xsl:attribute name="version">
> 			<xsl:value-of select="@version"/>
> 		</xsl:attribute>
> 		<xsl:attribute name="readVersion">
> 			<xsl:value-of select="@readVersion"/>
> 		</xsl:attribute>
> 		<xsl:copy-of select="*"/>
> 	</template>
> </xsl:template>
> </xsl:stylesheet>
> 	The transformation appears to work fine, except, as I 
> said, the child elements of the root <template> element, all 
> have the attribute xmlns="". A short snippet of it would be this:
> <?xml version="1.0" encoding="utf-8"?>
> <template xmlns="";
> xmlns:xsi=""; 
> version="3" readVersion="3">
>   <exportTimeStamp xmlns="">
>     <date>2003-12-29</date>
>     <time>15:31:34</time>
>   </exportTimeStamp>
>   <templateInfo xmlns="" name="" id="1139410602" revision="1">
>     ...
>   </templateInfo>
>   ...
> </template>
> 	I've found that if I change the namespace in the 
> <xsl:stylesheet> from xmlns to xmlns:y, then I don't get the 
> rogue attribute, but that is also giving me the incorrect 
> namespace. The source XML does not have any namespaces 
> defined within it, and I think that I read somewhere that the 
> <xsl:copy-of> might have issues with that. 
> 	Is there anyway to get the namespaces to come out 
> correctly, without giving me the xmlns=""?
> 	Erik Allen
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