Re: [xsl] Continue seqlist numbering

["G. Ken Holman" <gkholman@xxxxxxxxxxxxxxxxxxxx>]

At 2004-01-05 10:51 -0500, Norma Yeazell wrote:
> I have two seqlist lists in a row in my xml like:
>
> <seqlist>
> <item>this is item 1</item>
> <item>this is item 2</item>
> <item>this is item 3</item>
> </seqlist>
> <seqlist>
> <item>this is item 1</item>
> <item>this is item 2</item>
> <item>this is item 3</item>
> </seqlist>

Again, you are trying to infer a hierarchy where none exists.

> I can get it to number them but I need the second list to be numbered
> starting with the last item from the first list.
> I've tried <xsl:number count="item" level="multiple" format="1.1.1"/>

That relies on hierarchy in your input and one isn't there.

> The outcome should look like.
>
> 1. this is item 1
> 2. this is item 2
> 3. this is item 3
>
>     3.1. this is item 1
>     3.2. this is item 2
>     3.3. this is item 3

When doing the second <seqlist>, count the members in the first.  To 
generalize it, you will probably need to do something along the lines of 
the following from within an item:

  <xsl:for-each select="../preceding-sibling::seqlist">
    <xsl:value-of select="count(item)"/>.<xsl:text/>
  </xsl:for-each>
  <xsl:number/>. <xsl:text/>

The above should give you the following in the third <seqlist> list:

          3.3.1 this is item 1

I hope this helps.

................... Ken

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