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Subject: [xsl] Re: How to call a template that can generate a file name from an element From: Ian Lang <ianplang@xxxxxxxxx> Date: Sat, 17 Jan 2004 08:44:00 -0800 (PST) |
Oh how embarssing. Some how I missed reading digest
29 where Wendell pointed out my problem. All is well
when I change to:
<xsl:template name="createBaseFrameFileName">
<xsl:param name="element"/>
<xsl:value-of select="$element/@name"/>
</xsl:template>
Appologies and thanks for the help.
Ian
(who is going back to XPath school...)
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