[xsl] xsl variable, param: need references to full tree

[Simeon Ott <sot@xxxxxx>]

i've got the following xml as an example tree, and need to go through 
the tree, level based!:
as an example: "all title elements with level 0" should give me the 
element "title" with its childs commented as "element 1"
a 2nd example: "all title elements with level 1" should give me the 
elements "title" with its childs commented as "element 2" and "element 3"

<tablehead>
  <title> <!-- this is element 1 -->
    <value>Saldo letzter Abschluss</value>
    <cssclass>head</cssclass>
    <colwidth>250</colwidth>
    <visibility>visible</visibility>
    <layout>fixed</layout>
    <subtitles>
      <title> <!-- this is element 2 -->
        <value>Soll</value>
        <cssclass>head</cssclass>
        <colwidth>125</colwidth>
        <sortorder>no</sortorder>
      </title>
      <title> <!-- this is element 3 -->
        <value>Haben</value>
        <cssclass>head</cssclass>
        <colwidth>125</colwidth>
        <sortorder>no</sortorder>
      </title>
    </subtitles>
  </title>
</tablehead>

the following stylesheet do that (nearly) correct:

- call to template:
<xsl:call-template name="jumptolevel" >
  <!-- specify the level -->
  <xsl:with-param name="level" select="1" />
  <!-- root titles -->
  <xsl:with-param name="elements" select="/tablehead/title" />
</xsl:call-template>

- template itself:
<xsl:template name="jumptolevel">
  <xsl:param name="i" select="0" />
  <xsl:param name="level" select="0" />
  <xsl:param name="elements" />

  <xsl:choose>
    <xsl:when test="$i &lt; $level">
      <xsl:call-template name="jumptolevel">
        <xsl:with-param name="i" select="$i + 1" />
        <xsl:with-param name="level" select="$level" />
        <xsl:with-param name="elements" 
select="$elements/subtitles/title" />
      </xsl:call-template>
    </xsl:when>
    <xsl:otherwise>
      <xsl:copy-of select="$elements" />
    </xsl:otherwise>
  </xsl:choose>
</xsl:template>

the problem is, i need the result of the template "jumptolevel" as a 
reference in the whole tree.
when i call the template as followed

<xsl:variable name="test">
  <xsl:call-template name="jumptolevel" >
     <!-- specify the level -->
    <xsl:with-param name="level" select="1" />
     <!-- root titles -->
    <xsl:with-param name="elements" select="/tablehead/title" />
  </xsl:call-template>
</xsl:variable>
<xsl:value-of select="name($test/..)" />

i want to have "subtitles" displayed!
the result should give me also the parent nodes, how do i do that? or 
what i did wrong?

thanks in advance (sorry, for my bad english, i'm swiss ;)
jimmy

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