RE: [xsl] position

[m.vanrootseler@xxxxxxxxx]

Thanks Ken, this works. I hadn't thought of using <xsl:number/>. The
output, though, starts with '0', so the first note is numbered '0' but I
solved this by putting the lot into a variable and upping it by 1. 

Thanks for you help,

Mick


-----Oorspronkelijk bericht-----
Van: owner-xsl-list@xxxxxxxxxxxxxxxxxxxxxx
[mailto:owner-xsl-list@xxxxxxxxxxxxxxxxxxxxxx] Namens G. Ken Holman
Verzonden: 14 februari 2004 14:47
Aan: xsl-list@xxxxxxxxxxxxxxxxxxxxxx
Onderwerp: Re: [xsl] position

At 2004-02-14 14:02 +0100, m.vanrootseler@xxxxxxxxx wrote:
>I'm having trouble using position() in the following situation.
>...
>                         <xsl:for-each select="//note">
>                                 <xsl:value-of select="position()"/>

In the above you are setting the current node list to all of the notes,
and 
then using that for your count ... which works because of how you set
the 
current node list.

><xsl:template match="line">
>         <xsl:apply-templates/>

Above you are setting the current node list to the children of line, not
to 
anything related to note.

><xsl:template match="w">
>         <xsl:text> </xsl:text>
>         <xsl:apply-templates/>
>         <xsl:if test="note">
>                 <span
>style="vertical-align:super;font-size:7pt">*</span>
><!-- --------------------------------------------------------^ position
>should go here -->

Not "position" but the count of notes goes there ... remember that 
position() is *always* based on the current node list, and based on your

template rules your current node list is not comprised solely of <note> 
elements.

>Instead of the asterisk in the <span>, I'd like to put the value of the
>position of the <note> there,

The facility to count items in the source node tree is <xsl:number>:

    <xsl:number count="note" level="any"/>

>just like I did in the root template
>(where it works as it should),

"it works" because of how you prepared your current node list.  It is
also 
working in your other match, but you haven't prepared the current node
list 
accordingly, so you cannot use position() because it is based solely on
the 
current node list.

I hope this helps.

............................ Ken

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