[xsl] Re: XalanTransform warning: Invalid argument in nodeset()

["Dimitre Novatchev" <dnovatchev@xxxxxxxxx>]

"Prashant Thakare" <thakare@xxxxxxxxxxxxx> wrote in message
news:1078368756.7376.15.camel@xxxxxxxxxxxxxxxxxxxxxxxxxxxxx
> I am unable to get rid of warning "Invalid argument type in the function
> 'nodeset()'" given by XalanTransform.
>
> The code is as follows:
> <xsl:variable name="datatypes" select="/xip/datatypes"/>
> ...
> <xsl:with-param name="filters" select="xalan:nodeset($filters)"/>

I guess you meant:

   <xsl:with-param name="filters" select="xalan:nodeset($datatypes)"/>

The value of the "datataypes" variable is a node-set -- not an RTF. This is
why you get the warning.

In this case you do not need to use the xalan:nodset() extension function -- 
there's no RTF to cconver to a node-set.

> ...
>
> If I define the variable in the file instead of assigning from input
> file, the warning goes off.

Yes, because in this case the value of the "datatypes" is an RTF.


Cheers,

Dimitre Novatchev
FXSL developer,

http://fxsl.sourceforge.net/ -- the home of FXSL
Resume: http://fxsl.sf.net/DNovatchev/Resume/Res.html


>
> <xsl:variable name="datatypes">
> <abc>
>         <bcd>
>         </bcd>
> </abc>
> ...
> <xsl:with-param name="filters" select="xalan:nodeset($datatypes)"/>
> ...
>
> Any clues?
> Prashant
>
>
>  XSL-List info and archive:  http://www.mulberrytech.com/xsl/xsl-list
>
>




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