RE: [xsl] Generating HTML table

[cknell@xxxxxxxxxx]

Yes, I did one of these a few years ago. You will want to use the modulo operator on the value of the context node's position(). Here's how it's done:

<xsl:template match="/">
 <table>
   <xsl:for-each select="items/item">
     <xsl:choose>
       <xsl:when test="position() mod 4 = 1">
         <tr>
           <td><xsl:value-of select="."/></td>
           <td><xsl:value-of select="following-sibling::*[1]"/></td>
           <td><xsl:value-of select="following-sibling::*[2]"/></td>
           <td><xsl:value-of select="following-sibling::*[3]"/></td>
         </tr>
       </xsl:when>
       <xsl:otherwise></xsl:otherwise>
     </xsl:choose>
   </xsl:for-each>
 </table>
</xsl:template
-- 
Charles Knell
cknell@xxxxxxxxxx - email



-----Original Message-----
From:     Andreas Lindahl <andreas.lindahl@xxxxxxxxxx>
Sent:     Fri, 5 Mar 2004 13:10:32 +0100
To:       "'xsl-list@xxxxxxxxxxxxxxxxxxxxxx'" <xsl-list@xxxxxxxxxxxxxxxxxxxxxx>
Subject:  [xsl] Generating HTML table

Hi

My XML file looks like this:

<items>
	<item>Item 1</item>
	<item>Item 2</item>
	<item>Item 3</item>
	<item>Item 4</item>
	<item>Item 5</item>
	<item>Item 6</item>
	...
</item>

And I would like to create an HTML table which looks like this, from my XML
file:

<table>
	<tr>
		<td>
			Item 1
			Item 5
		</td>
		<td>
			Item 2
			Item 6
		</td>
		<td>
			Item 3
		</td>
		<td>
			Item 4
		</td>
	</tr>
</table>

I.e. four columns which are "populated" with items horisontally.

Is this possible to do with XSLT?

 XSL-List info and archive:  http://www.mulberrytech.com/xsl/xsl-list




 XSL-List info and archive:  http://www.mulberrytech.com/xsl/xsl-list