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Subject: RE: [xsl] Identity Transformations revisited From: "Andreas L. Delmelle" <a_l.delmelle@xxxxxxxxxx> Date: Sat, 6 Mar 2004 20:05:39 +0100 |
> -----Original Message-----
> From: Karl J. Stubsjoen
>
> Why can't I set up a for-each... and transform on each node and
> attribute of
> the result tree?
You *can* but that just wouldn't be the most elegant of solutions...
> Maybe I can not push an apply-templates... but
Yes you can, however, the snippet below will *only* give you the correct
output when there is a corresponding matching template defined.
>
> A correct template match is made here:
> <xsl:template match="campaign">
> <xsl:copy>
> <xsl:apply-templates select="@* | node()"/>
> </xsl:copy>
> </xsl:template>
>
In short: you also need at least something roughly like the following to go
with it
<xsl:template match="@* | node()">
<xsl:copy>
<xsl:apply-templates />
</xsl:copy>
</xsl:template>
Hope this helps!
Cheers,
Andreas
XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list
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