Subject: Re: [xsl] Cannot get numeric value - what am I doing wrong? From: Brian Chrisman <brian.chrisman@xxxxxx> Date: Thu, 18 Mar 2004 14:27:38 +0100 |
Hi all,Unless you are doing a xsl:value-of (or a few other things), you are getting back nodes from xpath expressions.
This is probably an easy question for you to answer, but I'm stumped.
I've got this variable I'm trying to assign a NUMERIC value to:
You can also do <xsl:value-of select="sum(/my/path/to/number)"/> To return the sum off all numbers in the 'number' nodes.
<xsl:variable name="top-remove"> <xsl:choose> <xsl:when test="string($prior-break-regions)"> <xsl:call-template name="add-up"> <xsl:with-param name="set-one" select="$prior-break-regions/@top"/> <xsl:with-param name="set-two" select="$prior-break-regions/@height"/> </xsl:call-template> </xsl:when> <xsl:otherwise><xsl:value-of select="number('0')"/></xsl:otherwise> </xsl:choose> </xsl:variable>
It calls a template, "add-up" which takes two sets of number node-sets and adds them all together. This, too, is supposed to return a NUMERIC value:
<xsl:template name="add-up"> <xsl:param name="set-one"/> <xsl:param name="set-two"/> <xsl:param name="index" select="1"/> <xsl:param name="total" select="0"/> <xsl:choose> <xsl:when test="$index > count($set-one) or $index > count($set-two)"> <xsl:value-of select="number($total)"/> </xsl:when> <xsl:otherwise> <xsl:call-template name="add-up"> <xsl:with-param name="set-one" select="$set-one"/> <xsl:with-param name="set-two" select="$set-two"/> <xsl:with-param name="total" select="$total + $set-one[$index] + $set-two[$index]"/> <xsl:with-param name="index" select="$index + 1"/> </xsl:call-template> </xsl:otherwise> </xsl:choose> </xsl:template>
So...HOW COME I wind up with a Node-Fragment type assigned to my variable, when all is said and done??? I need the value to be a numeric value, so that when I test to see if it is boolean true or false, it will react properly.
Thanks, KP
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