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[xsl] converting empty nodes to col/rowspan values

Subject: [xsl] converting empty nodes to col/rowspan values
From: "Reece, Michael Clark" <REECEM@xxxxxxxxxxxx>
Date: Tue, 13 Apr 2004 16:39:55 -0400
I am try to format an html with colspan and rowspan values for empty nodes.
For example with:
 
<?xml version="1.0"?>
<table>
  <row>
    <cell>Sample Table</cell>
    <cell></cell>
    <cell></cell>
    <cell></cell>
    <cell></cell>
  </row>
  <row>
    <cell>A</cell>
    <cell>B</cell>
    <cell></cell>
    <cell>C</cell>
    <cell></cell>
  </row>
  <row>
    <cell></cell>
    <cell>D</cell>
    <cell>E</cell>
    <cell>F</cell>
    <cell>G</cell>
  </row>
  <row>
    <cell>H</cell>
    <cell>I</cell>
    <cell>J</cell>
    <cell>K</cell>
    <cell></cell>
  </row>
</table>
 
I want the first row to be:
  <tr><td colspan=5>Sample Table</td></tr>
And the second row to be:
  <tr><td rowspan=2>A</td><td colspan=2>B</td><td colspan=2>C</td></tr>
 
And so forth...
 
This is my template:
 
<?xml version='1.0'?>
<xsl:stylesheet version="1.0"
xmlns:xsl="http://www.w3.org/1999/XSL/Transform
<http://www.w3.org/1999/XSL/Transform> ">
<xsl:template match="/">
      <html>
      <table border="1">
      <xsl:apply-templates/>
      </table>
      </html>
</xsl:template>
<xsl:template match="table">
      <xsl:for-each select="row">
            <tr><xsl:apply-templates/></tr>
      </xsl:for-each>
</xsl:template>
<xsl:template match="cell">
      <td><xsl:value-of select="."/></td>
</xsl:template>
</xsl:stylesheet>
 
I have tried many iterations but cannot figure this out.  Thanks...
 
Michael Reece
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