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Subject: RE: [xsl] XML Group with XSL From: aalikaj@xxxxxxxxxxxx Date: Thu, 22 Apr 2004 10:20:15 -0400 |
Hi All,
I'm still trying to solve my problem.
In a few words, i'm trying to explain my problem again.
I have an XML file with this format:
<ROOT>
<NODE1 ID = "1">
<NODE1_1_A ID="1">
<NODE1_1_1_A ID = "1">
<NODE1_1_1_1_A ID = "1">
data
</NODE1_1_1_1_A>
<NODE1_1_1_1_A ID = "2">
data
</NODE1_1_1_1_A>
</NODE1_1_1_A>
<NODE1_1_1_A ID = "2">
<NODE1_1_1_1_A ID = "1">
data
</NODE1_1_1_1_A>
<NODE1_1_1_1_A ID = "2">
data
</NODE1_1_1_1_A>
<NODE1_1_1_1_A ID = "3">
data
</NODE1_1_1_1_A>
</NODE1_1_1_A>
</NODE1_1_A>
<NODE1_1_A ID="2">
<NODE1_1_1_A ID = "1">
<NODE1_1_1_1_A ID = "1">
data
</NODE1_1_1_1_A>
<NODE1_1_1_1_A ID = "2">
data
</NODE1_1_1_1_A>
<NODE1_1_1_1_A ID = "3">
data
</NODE1_1_1_1_A>
</NODE1_1_1_A>
</NODE1_1_A>
</NODE1>
<NODE1 ID = "1">
<NODE1_1_A ID="1">
<NODE1_1_1_A ID = "1">
<NODE1_1_1_1_B ID = "1">
data
</NODE1_1_1_1_B>
<NODE1_1_1_1_B ID = "2">
data
</NODE1_1_1_1_B>
<NODE1_1_1_1_B ID = "3">
data
</NODE1_1_1_1_B>
</NODE1_1_1_A>
</NODE1_1_A>
</NODE1>
<NODE1 ID = "1">
<NODE1_1_A ID="1">
<NODE1_1_1_B ID = "1">
DATA
</NODE1_1_1_B>
<NODE1_1_1_B ID = "2">
DATA
</NODE1_1_1_B>
<NODE1_1_1_B ID = "3">
DATA
</NODE1_1_1_B>
</NODE1_1_A>
</NODE1>
<NODE1 ID = "1">
<NODE1_1_B ID="1">
DATA
</NODE1_1_B>
<NODE1_1_B ID="2">
DATA
</NODE1_1_B>
<NODE1_1_B ID="3">
DATA
</NODE1_1_B>
<NODE1_1_B ID="3">
DATA
</NODE1_1_B>
</NODE1>
</ROOT>
As you can see, the same node, with the same attributes, apears more than
once, so i want to collapse them. I want the following output
<ROOT>
<NODE1 ID = "1">
<NODE1_1_A ID="1">
<NODE1_1_1_A ID = "1">
<NODE1_1_1_1_A ID = "1">
data
</NODE1_1_1_1_A>
<NODE1_1_1_1_A ID = "2">
data
</NODE1_1_1_1_A>
<NODE1_1_1_1_B ID = "1">
data
</NODE1_1_1_1_B>
<NODE1_1_1_1_B ID = "2">
data
</NODE1_1_1_1_B>
<NODE1_1_1_1_B ID = "3">
data
</NODE1_1_1_1_B>
</NODE1_1_1_A>
<NODE1_1_1_A ID = "2">
<NODE1_1_1_1_A ID = "1">
data
</NODE1_1_1_1_A>
<NODE1_1_1_1_A ID = "2">
data
</NODE1_1_1_1_A>
<NODE1_1_1_1_A ID = "3">
data
</NODE1_1_1_1_A>
</NODE1_1_1_A>
<NODE1_1_1_B ID = "1">
DATA
</NODE1_1_1_B>
<NODE1_1_1_B ID = "2">
DATA
</NODE1_1_1_B>
<NODE1_1_1_B ID = "3">
DATA
</NODE1_1_1_B>
</NODE1_1_A>
<NODE1_1_A ID="2">
<NODE1_1_1_A ID = "1">
<NODE1_1_1_1_A ID = "1">
data
</NODE1_1_1_1_A>
<NODE1_1_1_1_A ID = "2">
data
</NODE1_1_1_1_A>
<NODE1_1_1_1_A ID = "3">
data
</NODE1_1_1_1_A>
</NODE1_1_1_A>
</NODE1_1_A>
<NODE1_1_B ID="1">
DATA
</NODE1_1_B>
<NODE1_1_B ID="2">
DATA
</NODE1_1_B>
<NODE1_1_B ID="3">
DATA
</NODE1_1_B>
<NODE1_1_B ID="3">
DATA
</NODE1_1_B>
</NODE1>
</ROOT>
I Can do this with DOM, but I want to use XSL if this is possible.
Thank you
Ardian Alikaj
Software Developer
Ntuitive Software & Systems.
E: aalikaj@xxxxxxxxxxxx
T: 416.863.9566 x326
F: 416.863.8919
"Michael Kay"
<mhk@xxxxxxxxx> To: <xsl-list@xxxxxxxxxxxxxxxxxxxxxx>
cc:
04/21/2004 06:31 Subject: RE: [xsl] XML Group with XSL
PM
Please respond to
xsl-list
> How can I exclude the node_1 from the following code
> <xsl:template match="node_1">
> <xsl:copy-of select="."/>
> </xsl:template>
>
> It prints out node_1 with its children. I want only children elements,
> because "node_1" has been prented once
Use <xsl:copy select="*">.
Michael Kay
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