|
Subject: [xsl] xsl:value-of problem From: Sam Saha <sam_saha1975@xxxxxxxx> Date: Tue, 27 Apr 2004 05:48:18 -0400 (EDT) |
Hello,
I have a template that has a param that denotes an
element name.
<xsl:template name="MyTemplate">
<xsl:param name="name"/>
<xsl:param name="pid"/>
<xsl:element name="{$name}">
<xsl:value-of select="ROOT/msg/data [ @id =$pid
]/$name" />
</xsl:element>
</xsl:template>
I have to access the value of the element in a
<xsl:value-of> as above. How do I do it? I know its
wrong the way I've done it above and I just wanted to
illustrate it. Can someone help at all? Thanks.
Sam.
______________________________________________________________________
Post your free ad now! http://personals.yahoo.ca
| Current Thread |
|---|
|
| <- Previous | Index | Next -> |
|---|---|---|
| RE: [xsl] tomcat web server and dyn, Michael Kay | Thread | Re: [xsl] xsl:value-of problem, Jeni Tennison |
| Re: [xsl] tomcat web server and dyn, Emmanuil Batsis (Man | Date | RE: [xsl] Sorting in Ancient Greek, Michael Kay |
| Month |