[xsl] XPath problem

Hi,

I still have a small problem with my modified "Pretty XML Tree Viewer (by Mike J. Brown and Jeni Tennison)

I stripped down the tree-view.xsl to a minimum.

My problem:

I get this as an output:

 tree
  |
  |___DB
      |
      |___Nina
            |
            |___Servus
            |     |
            |     |___Chip
            |
            |___Hallo
                  |
                  |___Warum
                  |     |
                  |     |___Serve
                  |
                  |___PC

But I want the tree starting from an other node; e.g. the node <nina>.

     tree
      |___Nina
            |
            |___Servus
            |     |
            |     |___Chip
            |
            |___Hallo
                  |
                  |___Warum
                  |     |
                  |     |___Serve
                  |
                  |___PC

tree-view.xml

<?xml version="1.0" encoding="utf-8"?>
<DB>
   <Nina>
       <Servus>
           <Chip/>
       </Servus>
       <Hallo>
           <Warum>
               <Serve/>
           </Warum>
           <PC/>
       </Hallo>
   </Nina>
</DB>

My stripped down tree-view.xsl:

<?xml version="1.0" encoding="utf-8"?> <xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform";> <xsl:output method="html" indent="no"/> <xsl:template match="/"> <html> <head> <title>tree-view by Mike J. Brown and Jeni Tennison</title> </head> <body> <h3>Can't find the solution for my problem</h3> <xsl:apply-templates select="." mode="render"/> </body> </html> </xsl:template> <xsl:template match="/" mode="render"> tree <br/> <xsl:apply-templates mode="render"/> </xsl:template> <xsl:template match="*" mode="render"> <xsl:call-template name="ascii-art-hierarchy"/> <br/> <xsl:call-template name="ascii-art-hierarchy"/>___ <xsl:value-of select="local-name()"/> <br/> <xsl:apply-templates mode="render"/> </xsl:template> <xsl:template name="ascii-art-hierarchy"> <xsl:for-each select="ancestor::*"> <xsl:choose> <xsl:when test="following-sibling::node()">  |   </xsl:when> <xsl:otherwise>      </xsl:otherwise> </xsl:choose> </xsl:for-each> <xsl:choose> <xsl:when test="parent::node() and ../child::node()">  |</xsl:when> <xsl:otherwise>   </xsl:otherwise> </xsl:choose> </xsl:template> </xsl:stylesheet>

I couldn' solve the problem myself.

Anyone got an idea?

Thanks
Jonny

_________________________________________________________________ MSN Messenger - sehen, welche Freunde online sind! http://www.msn.de/messenger Jetzt kostenlos downloaden und mitmachen!

<- Previous	Index	Next ->
RE: [xsl] Transforming elements int, Daniel Joshua	Thread	Re: [xsl] XPath problem, Tom Schutzer-Weissma
AW: AW: AW: AW: [xsl] tomcat web se, Nikolas Nehmer	Date	AW: AW: AW: AW: [xsl] tomcat web se, Nikolas Nehmer
	Month

<-prev [Thread] next->	<-prev [Date] next->
Month Index \| List Home