Re: [xsl] [solved]Generating a tree

[Wendell Piez <wapiez@xxxxxxxxxxxxxxxx>]

At 06:34 PM 5/4/2004, you wrote:
> Problem solved.

Only apparently.

> Something like this made it work (you're welcome if you have some 
> suggestion to simplify or optimize) :
>
> <xsl:template name="pageNav">
>   <xsl:param name="targetNode"/>
>   <xsl:param name="currentNode"/>
>   <div class="sectionNav">
>     <xsl:for-each select="$currentNode/section|$currentNode/page">
>       <li>
>         <a href="{$url}?page={@name}">
>           <xsl:value-of select="@title"/></a>
>         <xsl:if test=". = $targetNode/ancestor-or-self::section">

This test compares the string value of the current node to the string 
values of all ancestors of the target node, or the target node itself. It 
will yield the result you want only most of the time.

For a true node-identity test look at my earlier post in this thread.

Otherwise a cursory scan looks good. I like the recursive call of the 
template: it simplifies things.

>           <ul>
>             <xsl:call-template name="pageNav">
>               <xsl:with-param name="targetNode" select="$targetNode"/>
>               <xsl:with-param name="currentNode" select="."/>
>             </xsl:call-template>
>           </ul>
>         </xsl:if>
>       </li>
>     </xsl:for-each>
>   </div>
> </xsl:template>

Oh, and I note this outputs HTML, whereas the OP seemed to be asking for 
plain text. (Hey who's quibbling?)

Cheers,
Wendell


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Wendell Piez                            mailto:wapiez@xxxxxxxxxxxxxxxx
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