Very Basic Generic Filtering Question

[Arvind Bassi <arvind_bassi@xxxxxxxxxxx>]

I haven't done XSLT for quite some time, and its amazing how much l
have forgotten.

I have a very simple problem of having to filter out a specific xml
element. In the example below, it is <Header>, but it should be able to
be passed down as a parameter. From memory, l need to use the name
function and test it against the current node, but l have tried doing
this but to no avail.

How can the following xml document be filtered in a generic manner?


<?xml version="1.0" encoding="UTF-8"?>
<AddressBook>
    <Header>
        <ElementOne id="1">hello</ElementOne>
        <ElementTwo id="2"> why not</ElementTwo>
    </Header>
    <People value="3">
        <Name number="3">
            <FirstName> Simon</FirstName>
            <LastName>Says</LastName>
        </Name>
        <Name number="3">
            <FirstName> Simon</FirstName>
            <LastName>Says</LastName>
        </Name>
        <Name number="3">
            <FirstName> Simon</FirstName>
            <LastName>Says</LastName>
        </Name>
        <Name number="3">
            <FirstName> Simon</FirstName>
            <LastName>Says</LastName>
        </Name>
    </People>
    <Mary>
        <Had a="little"> lamb</Had>
    </Mary>
</AddressBook>


<?xml version="1.0" encoding="UTF-8"?>
<xsl:stylesheet version="1.1"
xmlns:xsl="http://www.w3.org/1999/XSL/Transform";>
    <xsl:output indent="yes" method="xml" version="1.0"/>
    <xsl:param name="filterElement">Header</xsl:param>
    <xsl:template match="/">
        <xsl:copy>
            <xsl:apply-templates/>
        </xsl:copy>
    </xsl:template>
    <xsl:template match="???????">
        <xsl:copy-of select="."/>
    </xsl:template>
    <xsl:template match="????????"/>
</xsl:stylesheet>

Any help that can be provided would be gratefully appreciated.

Thanks.

Arvind.





	
	
		
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