| Subject: testing for last node of antecesor From: CACTUS_JIROPA <CACTUS_JIROPA@xxxxxxxx> Date: Fri, 11 Jun 2004 17:49:12 +0200 | 
Hello, I have a XML like this:
<listado>
  <report>
  </report>
  <pagina>
  </pagina>
  <detalle>
    <resumen>
    </resumen>
    <datos>
      <reg>
        <campoReg>
        </campoReg>
        <detalle>
          <cabecera>
          </cabecera>
          <pie>
            <campoPie>
              <nombre>break</nombre>
            </campoPie>
          </pie>
          <resumen>
          </resumen>
          <datos>
          </datos>
        </detalle>
      </reg>
      <reg>
        <campoReg>
        </campoReg>
        <detalle>
          <cabecera>
          </cabecera>
          <pie>
            <campoPie>
              <nombre>break</nombre>
            </campoPie>
          </pie>
          <resumen>
          </resumen>
          <datos>
          </datos>
        </detalle>
      </reg>
    </datos>
    <cabecera>
    </cabecera>
    <pie>
      <campoPie>
        <nombre>break</nombre>
      </campoPie>
    </pie>
  </detalle>
</listado>
The problem is than when I evaluate node //detalle/pie/campoPie/nombre,
in any of its recursive levels, I want to test if that 'detalle' node (
that is always antecesor of 'nombre' ) is the last in his level.
In other words, this is the structure of a report, I want to introduce a
page break when I find 'break' value in 'nombre' node, but omits this
break in the last node.
I think I have test:
<xsl:if test="ancestor::detalle [position() != last()]"> 
but it always evaluate to true.
any ideas?
Thank you 
Sergio Roldan Castillo
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